2(x-1)^2+5(x-1)-3=0

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Solution for 2(x-1)^2+5(x-1)-3=0 equation: 



2(x-1)^2+5(x-1)-3=0

We multiply parentheses

2(x-1)^2+5x-5-3=0

We add all the numbers together, and all the variables

5x+2(x-1)^2-8=0

We move all terms containing x to the left, all other terms to the right

5x+2(x-1)^2=8

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